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4x^2-4x-810=0
a = 4; b = -4; c = -810;
Δ = b2-4ac
Δ = -42-4·4·(-810)
Δ = 12976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12976}=\sqrt{16*811}=\sqrt{16}*\sqrt{811}=4\sqrt{811}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{811}}{2*4}=\frac{4-4\sqrt{811}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{811}}{2*4}=\frac{4+4\sqrt{811}}{8} $
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